21x-2^2=38x+5

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Solution for 21x-2^2=38x+5 equation: 



21x-2^2=38x+5

We move all terms to the left:

21x-2^2-(38x+5)=0

We add all the numbers together, and all the variables

21x-(38x+5)-4=0

We get rid of parentheses

21x-38x-5-4=0

We add all the numbers together, and all the variables

-17x-9=0

We move all terms containing x to the left, all other terms to the right

-17x=9

x=9/-17

x=-9/17

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